k^2-31-2k=^2-2k

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Solution for k^2-31-2k=^2-2k equation: 



k^2-31-2k=^2-2k

We move all terms to the left:

k^2-31-2k-(^2-2k)=0

We get rid of parentheses

k^2-2k+2k-31-^2=0

We add all the numbers together, and all the variables

k^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{2}=0$

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